2y3x(x^3/2)=

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Solution for 2y3x(x^3/2)= equation: 


((x^2-(3*x)+2)/(x^2-(7*x)+12))^(1/2)

7 = y/(-0.6)

5*x+10*y-23;2*x+6*y-15

X = 20/1

16/3-(101/9) = 0

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